A.Max[i,j]= Allocation[i,j]+Need[i,j]
B.Need[i,j]= Max[i,j]- Allocation[i,j]
C.Max[i,j]= Allocation[i,j]-Need[i,j]
D.Need[i,j]= Max[i,j]+Allocation[i,j]
答案： <查看本题扣1积分>
查看答案
答案不对？请尝试站内搜索