当前学科:汇编语言程序设计
  • 题目: 问答题

      现有(DS)=2000H,(BX)=0100H,(SI)=0002H,(20100H)=12H,(20101H)=34H,(20102H)=56H,(20103H)=78H,(21200H)=2AH,(21201H)=4CH,(21202H)=0B7H,(21203H)=65H,说明下列指令执行后AX寄存器的内容。
      (1)MOVAX,1200H
      (2)MOVAX,BX
      (3)MOVAX,[1200H]
      (4)MOVAX,[BX]
      (5)MOVAX,1100H[BX]
      (6)MOVAX,[BX][SI]
      (7)MOVAX,1100H[BX][SI]

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